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Lösung 3.3:3d

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Before we can complete the square of the expression, we need to take out the factor i in front of z2,

iz2+i2+3izi1. 

Then, simplify the complex fractions by multiplying top and bottom by i (the denominator's complex conjugate),

iz2+i(i)(2+3i)(i)zi(i)1(i)=iz2+12i+3z1i=iz2+(32i)z+i.

Now we are ready to complete the square of the second-degree expression inside the bracket,

iz2+(32i)z+i=iz+232i2232i2+i=iz+23i223i2+i=iz+23i249+3ii2+i=iz+23i245+4i=iz+23i245i+4i2=iz+23i2445i.