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1.1:2a alternativ 1

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f(x)=limh0hf(x+h)f(x) wobei f(x)=x23x+1 f(x)=limh0h(x+h)23(x+h)+1(x23x+1)=limh0hx2+2hx+h23x3h+1x2+3x+1=limh0h2hx+h23h=limh02x+h3=2x3