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Lösung 3.2:4b

Aus Online Mathematik Brückenkurs 2

(Unterschied zwischen Versionen)
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K (Robot: Automated text replacement (-{{Displayed math +{{Abgesetzte Formel))
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We calculate what the expression will be
We calculate what the expression will be
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{{Displayed math||<math>(2-i)+(5+3i) = 2+5+(-1+3)i = 7+2i</math>}}
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{{Abgesetzte Formel||<math>(2-i)+(5+3i) = 2+5+(-1+3)i = 7+2i</math>}}
and then calculate the magnitude,
and then calculate the magnitude,
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{{Displayed math||<math>|7+2i| = \sqrt{7^2+2^2} = \sqrt{49+4} = \sqrt{53}\,\textrm{.}</math>}}
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{{Abgesetzte Formel||<math>|7+2i| = \sqrt{7^2+2^2} = \sqrt{49+4} = \sqrt{53}\,\textrm{.}</math>}}
Note: It is not possible to calculate the magnitude of the terms individually
Note: It is not possible to calculate the magnitude of the terms individually
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{{Displayed math||<math>|(2-i)+(5+3i)| \ne |2-i| + |5+3i|\,\textrm{.}</math>}}
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{{Abgesetzte Formel||<math>|(2-i)+(5+3i)| \ne |2-i| + |5+3i|\,\textrm{.}</math>}}

Version vom 13:08, 10. Mär. 2009

We calculate what the expression will be

(2−i)+(5+3i)=2+5+(−1+3)i=7+2i

and then calculate the magnitude,

7+2i=72+22=49+4=53. 


Note: It is not possible to calculate the magnitude of the terms individually

(2−i)+(5+3i)=2−i+5+3i.
Von „http://wiki.math.se/wikis/2009/bridgecourse2-TU-Berlin/index.php/L%C3%B6sung_3.2:4b“