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Lösung 3.1:1e

Aus Online Mathematik Brückenkurs 2

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A suitable first step can be to work out the square term, (2i)2, by expanding it,

(2i)2=2222i+i2=44i+i2=44i1=34i.

After that, we calculate the remaining product,

(1+i)(34i)=1314i+i3i4i=34i+3i4i2=3+(4+3)i4(1)=3i+4=7i.